f(x)=x63−2x

ddx[x63−2x]
=ddx[x6]3−2⋅ddx[x]
=6x53−2⋅1
=2x5−2

f(x)=(x3−2x)⋅(x5+6x2)

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f(x)=x63−2x

ddx[x63−2x]
=ddx[x6]3−2⋅ddx[x]
=6x53−2⋅1
=2x5−2

f(x)=(x3−2x)⋅(x5+6x2)

Sign up here with your email

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